Prevalensi sunat: Perbedaan antara revisi
Konten dihapus Konten ditambahkan
Baris 66:
==Asia==
===Kurang dari 20%===
Bhutan, Myanmar, Kamboja, China, Hong Kong (China),<ref>http://smj.sma.org.sg/2302/2302smj6.pdf</ref> India, Jepang, Laos, Mongolia, Nepal, Korea Utara, Papua Nugini, Sri Lanka, Taiwan, Thailand, Vietnam.<ref name="WHO" />
Prevalensi keseluruhan sunat di Kamboja dilaporkan 3,5%.<ref name="castellsague" />
===Antara 20 dan 80%===
Kazakhstan, Indonesia, Malaysia,<ref name="WHO" /> Korea Selatan.<ref name="Kimetal">Kim et al.: Decline in male circumcision in South
Korea. BMC Public Health 2012 12:1067. http://www.biomedcentral.com/content/pdf/1471-2458-12-1067.pdf</ref>
====Korea Selatan====
Baris 78 ⟶ 79:
===Lebih dari 80%===
Afganistan, Azerbaijan, Bahrain, Bangladesh, Brunei, Filipina, Iran, Irak, Israel,<ref name="ynet1106">{{cite web |title=Israel teaches WHO about circumcision |publisher=ynet news |date=November 2006 |url=http://www.ynetnews.com/articles/0,7340,L-3333564,00.html}}</ref> Kuwait, Kirgizstan, Lebanon, Oman, Pakistan,<ref name="castellsague" /> Qatar, Saudi Arabia, Suriah, Tajikistan, Turki, Turkmenistan, Uzbekistan, Uni Emirat Arab, Yaman, Yordania.<ref name="WHO" />
Prevalensi sunat (''[[tuli (ritual)|tuli]]'') keseluruhan di Filipina dilaporkan 92,5%. Sebagian sunat di Filipina dilakukan pada usia 11 sampai 13 tahun.<ref>{{cite journal|last=Darby|first=Robert|title=Routine peripubertal circumcision?|publisher=[[National Institutes of Health]]|date=9 August 2011|pmc=3153524|volume=183|issue=11|pages=1283–1284|doi=10.1503/cmaj.111-2060|journal=CMAJ : Canadian Medical Association Journal}}</ref><ref>{{cite web|last=Ong|first=Christine|title=Philippine doctors question medical benefits of circumcision|url=http://www.channelnewsasia.com/stories/southeastasia/view/350729/1/.html|work=Channel News Asia|publisher=MediaCorp|accessdate=27 August 2012|date=29 May 2008}}</ref>
Menurut Jerusalem AIDS Project, "sekitar 100 persen laki-laki telah disunat" di Israel.<ref name="ynet1106" />
==Eropa==
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