Fungsi hiperbolik: Perbedaan antara revisi

\end{align}</math>

 

Pembuktian <math>arcsinh x = ln (x + \sqrt{x^2 + 1})</math>!

: <math>y = arcsinh x</math>

: <math>y = ln (x + \sqrt{x^2 + 1})</math>

: <math>arcsinh x = ln (x + \sqrt{x^2 + 1})</math>

 

== Turunan ==